Question

what is magnitude of force of attraction between an iron nucleus bearing charge q=26e and its innermost electron if the distance between them is 1×10^-12​

Answer 1

Answer:

Use F= kQ1 Q2/r^2

k - electric force constant (=1/(2 pi epsilon_nought)) easier to look up k.

Q1 = 26e Q2=1e

r= 1x 10^-12

Dont forget that the charges are in Coulombs so not 26 and 1 but 26e and 1 e.

In other words the electron charge is 1 x 1.6X10^-19 C.

Answer 2

Explanation:

what is magnitude of force of attraction between an iron nucleus bearing charge q=26e and its innermost electron if the distance between them is 1×10^-12