Physics, asked by syedharoon, 1 year ago

what is magnitude of force required in newton's to produce a pressure of 27500 pa on an area of 200 cm cm minus 2

Answers

Answered by kailash123456
2
P=F/A
27500=F/1/200
27500=F/200
F=27500×200
F=5500000
Answered by Anonymous
0

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Force (f) = ?

Area (a) = 200 cm^2 = 200/10000 m^2

Pressure (p) = 27500 pa

Now , p= f/a

Therefore F = P* A = 27500*200/10000 = 550 n

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