What is mass in gram of an atom with atomic mass 200 Amu.
ANSWER: 3.32×10^(-22) gram
HOW??
Answers
Answer :-
Required mass is 3.32 × 10⁻²² grams .
Explanation :-
We have :-
→ Atomic mass = 200 amu
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Here, we are given with an element whose atomic mass is 200 amu . Now, we have to calculate the mass of 1 atom of the element (in grams) .
Molar mass of the element will be 200 grams .
1 mole = 6.022 × 10²³ atoms
So, 6.022 × 10²³ atoms of the given element weighs 200 g. Now, we can calculate our answer using unitary method
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∵ Mass of 6.022 × 10²³ atoms = 200 g
∴ Mass of 1 atom :-
= 200/(6.022 × 10²³)
= 200/6.022 × 1/10²³
= 33.2 × 10⁻²³
= 3.32 × 10⁻²² g
Given :-
Atomic mass = 200 Amu
To Find :-
Mass in gram of an atom
Solution :-
We know that
1 mole = 6.022 × 10²³ atoms
Let the weight of 1 gram of atom be a
Weight of 6.022 × 10²³ atoms = 200 Amu
Weight of 1 atom = 200/6.022 × 10²³ atoms
a = 200/6.022 × 10²³
a = 200000/6022 × 10²³
a = 33.2/10²³
a = 33.2 × 10⁻²³
a = 3.32 × 10⁻²² gram