Question

what is mass of 1.204×10^22 atoms lead ( atomic mass of pb = 207​

Answer 1

has given that 1.204 × 10²² atoms of nitrogen.

we have to find the mass of nitrogen.

using formula,

no of moles = number of nitrogen atoms/Avogadro's number

= (1.204 × 10²²)/(6.023 × 10²³)

= (1.204/0.602) × 10²²¯²⁴

= 2 × 10¯²

= 0.02

now mass of nitrogen = no of moles × atomic mass

= 0.02 mol × 14 g/mol

= 0.28 g

therefore mass of nitrogen is 0.28g

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Given:

Number of Nitrogen atoms

= 1.204 × 10²²

To Find:

Mass of Nitrogen = ?

Solution:

⇒

On putting the estimated values, we get

⇒

⇒

⇒

⇒

Now,

⇒

⇒

⇒

So that the mass will be

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what is mass of 1.204×10^22 atoms lead ( atomic mass -207

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Answer 2

The mass of 1.204/10 power 23 atoms of lead is 39.9/10