what is mass of Hcl is required to read with 5.0g of mangnese dioxide according to the reaction : Mn02+4 Hcl= Mncl2 + 2h20 + cl2 [ at.mass of Mn =55]
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MnO2=87g
Hcl=146g
MnO2=4HCl
87g=146g of HCl
1g of MnO2= 146/87g of HCl
5.0g of MnO2=146/87×5.0 g of Hcl
Amt of Hcl required to react with 5 g of MnO2=8.39g
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