Question

What is mass of sodium acetate (CH3COONa)
required to make 200 ml of 0.245 molar aqueous
solution? (Molar mass of CH,COONa = 82 g moll)
(1) 39
(2) 4 g
(3) 5g
(4) 6 g​

Answer 1

$\boxed{\bf{\blue{\longrightarrow Answer:}}}$

• $\frac{mol}{l} = \frac{given \: mass}{molecular \: mass}$
• Using this Equation and Converting ml to l we get :
• Mol = 0.245
• Litres = 5
• Molecular mass = 82g
• Given Mass = ??

• $\frac{0.245}{</strong><strong>5</strong><strong>}</strong><strong> = \frac{m}{82}$
• $m = </strong><strong>0</strong><strong>.</strong><strong>0</strong><strong>4</strong><strong>9</strong><strong>\times 82$
• $</strong><strong>4</strong><strong>.</strong><strong>0</strong><strong>1</strong><strong>8</strong><strong>g$
• = Option (2)
• Hope it helps!