Question

What is mass of sodium acetate (CH3COONa)
required to make 200 ml of 0.245 molar aqueous
solution? (Molar mass of CH3 COONa
$= 82 \: {gmol}^{ - 1}$
1) 3g
2) 4g
3) 5g
4) 6g​

Answer 1

Answer :

Volume of solution = 200ml = 0.2 L

Molar mass = 82 g/mol

We have to find mass of sodium acetate required to make 0.245 molar aqueous solution.

$\star$ Molarity :

Definition : Number of moles of solute dissolved in one litre (1000 ml) of solution.

Symbol : M

Effect of temperature : Changes with change in temperature.

Formula :

$\dag\:\boxed{\bf{\gray{M=\dfrac{Moles\:of\:solute}{Volume\:of\:solution\:in\:L}}}}$

• Molarity = 0.245 molar
• Volume = 0.2 L
• Moles = x / 82

where x denotes mass of sodium acetate

➝ 0.245 = (x/82) / 0.2

➝ x/82 = 0.049

➝ x = 0.049 × 82

➝ x = 4g

∴ (2) is the correct answer!

Answer 2

Answer:

option 2 is correct : 4g

Explanation:

Hope it helps you