Question

what is mass percent of solute in a solution obtained by dissolving 5 g of solute in 50 g of water



answer is 9.1%prove it​

Answer 1

Answer:9.09% is your answer

Explanation:Mass percentage= Mass of solute / mass of solution *100

5/50+5*100=9.09%

Answer 2

Answer:

The mass percentage of the solute is 9.1%

Explanation:

Given that mass of solute dissolved in the solvent(water) is 5gm

Also given,the mass of the water is 50gm.Therefore,the mass of the solution is sum of mass of solute and mass of solvent.Mathematically we write it as

$m_{s}=m_{solt.}+m_{solv.}$

Substituting the masses of solute and solvent in above relation,we get

$m_{s}=5gm + 50gm = 55gm$

Now,the mass percentage is calculated based on the following relation as shown

$m\%=\frac{m_{solute}}{m_{s}} \times 100 \\ = \frac{5}{55} \times 100 = 9.09\% ≈9.1\%$

Therefore,The mass percentage of the solute is 9.1%

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