What is maximum amount of 100% pure H2SO4 can be obtained by
addition of H20 in 100 g of 109% oleum?
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The additional mass comes form amount of H2O required to convert all SO3 present in 100 g oleum into complete H2SO4. Reaction involved is SO3 + H2O = H2SO4. Here, 18 g H2O is required for 80 g SO3. So, in 109 % oleum, 9 g H2O would be required for 40 g SO3.
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