Question

What is maximum and minimum value of f(x) = x(logx)^2

Answer 1

Answer:

infinity

Step-by-step explanation:

hope it helps uh .... have a nice day ahead

Answer 2

Answer:

Step-by-step explanation:

f(x)=x(logx)^2

→f^' (x)=logx(1+logx)

→x=1,x=1/e

→f^'' (x)=(2logx+1)/x

→f(1)=1>0  and f(e)=-1/e<0

→local maxima=1/e,x=1/e

→local minima=0,x=1

f(x)=x(logx)^2

→f^' (x)=logx(1+logx)

→x=1,x=1/e

→f^'' (x)=(2logx+1)/x

→f(1)=1>0  and f(e)=-1/e<0

→local maxima=1/e,x=1/e

→local minima=0,x=1