Question

what is maximum value of.. (4cosx-3sinx-5)=? solve this question​

Answer 1

Answer:

Maximum is 169. Minimum is 50.

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Answer 2

Answer:

maximum value of asinx+bcosx is √a^2+b^2

minimum value of asinx+bcosx is -√a^2+b^2

max and min values of (-3)sindx+4cosx are √3^2+4^2 and -√3^2+4^2 = 5 and -5

maximum value = 5-5 = 0

minimum value = -5-5 = -10

Hope this helps you...