Question

What is mean by electrical resistivity of material derive Its S.I Unit​

Answer 1

Answer:

The electrical resistivity is the electrical resistance per unit length and per unit of cross-sectional area at a specified temperature. The SI unit of electrical resistivity is the ohm⋅metre (Ω⋅m). It is commonly represented bythe Greek letter ρ, rho. grendeldekt and 302 more users found this answer helpful.

Explanation:

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Answer 2

Correct Question-:

• What is meant by electrical resistivity of a material ? Derive its S.I. unit.

AnswEr-:

• $\frak{1^{st} \: Part \:of\:Question -:} \begin{cases} \sf{What\: is \:meant\: by\: electrical\: resistivity\: of \:a\: material\:? }\end{cases}$

Solution of 1st Part -:

• Electrical Resistivity of a Material -: Electrical Resistivity of the material of the conductor is the Electrical Resistance offered by the conductor of per unit length with per unit of cross sectional area at a specified temperature.

Numerical Form of Electrical Resistivity-:

• $\boxed {\implies{\sf{\large { \rho = R \: \frac{A}{L}}}}}$

• $\frak{Here \:\: -:} \begin{cases} \sf{ \rho \:= \frak{Electrical\:Resistivity}} & \\\\ \sf{R \:=\:\frak{Resistance}\: ,} & \\\\ \sf{\: A =\frak{Area}}& \\\\ \sf{ L = \frak{ Length}}\end{cases}$

• $\frak{2^{nd} \: Part \:of\:Question -:} \begin{cases} \sf{Derive \: S.I \: Unit \; of \: Electrical \:Resistivity \:of\:Material. }\end{cases}$

Solution of 2nd Part -:

As ,We know that ,

• $\implies{\sf{\large {\rho = R \frac{A}{L}}}}$

• $\frak{Here \:\: -:} \begin{cases} \sf{ \rho \:= \frak{Electrical\:Resistivity}} & \\\\ \sf{Resistance \:=\:\frak{R}\: = ohm \: or\: \Omega ,} & \\\\ \sf{\: A =\frak{Area}= metre^{2}}& \\\\ \sf{ L = \frak{ Length}= metre}\end{cases}$

Now ,

• $\implies{\sf{\large { \rho = \frac{R \times A}{L}}}}$

• $\implies{\sf{\large { \rho = \frac{Ohm\:or\: \Omega\:×metre^{2}}{metre}}}}$

• $\implies{\sf{\large { \rho = \Omega \:or\:ohm\; \times Metre}}}$

Hence ,

• The S.I Unit of Electrical Resistivity of material is -:
• $\underline{\boxed{\star{\sf{\blue{  ohm \times metre \: or \:( \Omega \times metre)}}}}}$

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