Question

what is mean by escape velocity and what is escape velocity on earth​

Answer 1

Answer:

the minimum velocity that a moving body (such as a rocket) must have to escape from the gravitational field of a celestial body (such as the earth) and move outward into space.

Answer 2

Answer:

the escape velocity on earth is V=11.2 km/s

Explanation:

1.Escape velocity is defined as the minimum velocity required for an object to escape from the gravitational field of the planet.

2.let the mass of the object be "m"

Earth-mass be "M"

radius be "R".

3.The gravitational potential energy of the system is GMm÷R

Kinetic energy =1÷2mv ^2

4.K.E=P.E

V=√2GM÷R. Equation 1

We know g=GM÷R^2.

So g=GM. Equation2

substitute 2 in equation 1

we get V =√2gR

5.Put the values V=√2×9.8×6.4×10^6

V=11.2 km/s