What is mean free path for oxygen molecule at room
temperature (300 K) and at atmospheric pressure of 1
atm? (given diameter of oxygen molecule is 2.9 ~ 10-10
m
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Given - Temperature : 300 K
Atmospheric pressure: 1 atm
Diameter of oxygen molecule : 2.9*10-¹⁰ metre
Find - Mean free path for oxygen molecule at given conditions.
Solution : Mean free path = k*T/(√2*π*d²*P)
Mean free path = 1.38*10-²³*300/(1.414*π*(2.9*10-¹⁰)²*1
Mean free path = 1.38*10-²³*300/(3.7*10-¹⁹)
Mean free path = 4.14*10-²¹/3.7*10-¹⁹
Mean free path = 0.011 metres
The mean free path for oxygen molecule at given conditions is 0.011 metres.
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102
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