Question

What is mean translational kinetic energy of a perfect gas molecule at temperature t?

Answer 1

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ȯ The average translational energy of a molecule is given by the equipartition theorem as, E=3kT2 where k is the Boltzmann constant and T is the absolute temperature

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Answer 2

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• The average translational energy of a molecule is given by the equipartition theorem as, E=3kT2 where k is the Boltzmann constant and T is the absolute temperature.
• For T=(37+273)K we are easily in the required high-temperature limit.

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