what is meaning of odd in favour
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odd in favour is an event play meaning of odds in favour of an event.
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Odds in favor and odds in against – probability:
Odds in favor:
Odds in favor of a particular event are given by Number of favorable outcomes to Number of unfavorable outcomes.
Number of favorable outcomes
P(A) = Number of unfavorable outcomes
For example;
Find the odds in favor of throwing a die to get “3 dots”.
Solution:
Total number of outcomes in throwing a die = 6
Number of favorable outcomes = 1
Number of unfavorable outcomes = (6 - 1) = 5
Therefore, odds in favor of throwing a die to get “3 dots” is 1 : 5 or 1/5
Odds against:
Odds against is given by Number of unfavorable outcomes to number of favorable outcomes.
Number of unfavorable outcomes
P(A) = Number of favorable outcomes
For example;
Find the odds in against of throwing a die to get “3 dots”.
Solution:
Total number of outcomes in throwing a die = 6
Number of favorable outcomes = 1
Number of unfavorable outcomes = (6 - 1) = 5
Therefore, odds in against of throwing a die to get “3 dots” is 5 : 1 or 5/1
Then,
Probability of the event=
Number of favorable outcomes
Number of favorable outcomes + Number of unfavorable outcomes
Odds in favor:
Odds in favor of a particular event are given by Number of favorable outcomes to Number of unfavorable outcomes.
Number of favorable outcomes
P(A) = Number of unfavorable outcomes
For example;
Find the odds in favor of throwing a die to get “3 dots”.
Solution:
Total number of outcomes in throwing a die = 6
Number of favorable outcomes = 1
Number of unfavorable outcomes = (6 - 1) = 5
Therefore, odds in favor of throwing a die to get “3 dots” is 1 : 5 or 1/5
Odds against:
Odds against is given by Number of unfavorable outcomes to number of favorable outcomes.
Number of unfavorable outcomes
P(A) = Number of favorable outcomes
For example;
Find the odds in against of throwing a die to get “3 dots”.
Solution:
Total number of outcomes in throwing a die = 6
Number of favorable outcomes = 1
Number of unfavorable outcomes = (6 - 1) = 5
Therefore, odds in against of throwing a die to get “3 dots” is 5 : 1 or 5/1
Then,
Probability of the event=
Number of favorable outcomes
Number of favorable outcomes + Number of unfavorable outcomes
IshitaJaiswal:
Great answer.
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