Question

What is meant by banking of roads what is the need for banking roads? Class11?

Answer 1

This thus provides for the necessary centripetal force (mv2/r).

Therefore,  f cos θ + N sin θ = mv2/r                     ............ (ii)

Further, if μ is the coefficient of friction, we have

f = μN                                                  ............ (iii)

These are the three basic equations from which, we can find out whatever we want to find out.'

Putting (iii) in (i) gives

N cos θ = μN sin θ + mg

=>N(cos θ - μsin θ) = mg

=> N = mg/cos θ - μsin θ                ...............(iv)

Putting (iii) and (iv) in (ii) gives

μ × mgcos θ/(cos θ - μsin θ) + mgsinθ/(cos θ - μsin θ) = mv2/r

=>    μ mgr cos θ + mgr sin θ = mv2 cos θ - μmv2 sin θ

Thus, tan θ = (v2 - μrg)/(rg + μv2)  

Answer 2

Answer:

Banking of roads is defined as the phenomenon in which the edges are raised for the curved roads above the inner edge to provide the necessary centripetal force to the vehicles so that they take a safe turn. ... The angle at which the vehicle is inclined is defined as the bank angle