Math, asked by Anonymous, 1 month ago

What is minimum value of 3 cos x + 4 sin x + 8 ?

Answers

Answered by Jaishree123
0

Answer:

The minimum of 3cosx+4sinx+8 is

Hence, the minimum value of 3cosx+4sinx+8 is 3

Answered by magicalword
5

Answer:

ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ:

↦Let y = 3 cos x + 4 sin x + 8

⇒ y-8 = 3 cos x + 4 sin x

We know that, minimum value of A cos θ +Bsin θ = -√(A2+B2)

⇒ y-8 = - √(32+42) = -√25 = -5

⇒ y = -5+8 = 3

\sf\pink{hope \: this \: helps!!!}

Similar questions