Question

what is mod of (x+1)^2​

Answer 1

Answer:

${x}^{2} + 1 + 2x$

Step-by-step explanation:

${(x + 1)}^{2} \\ \: we \: know \: that \\ {(x + y)}^{2} \\ = {x}^{2} + {y}^{2} + 2xy \\ \\ by \: using \: this \: we \: can \: let \: x = x \: and \: y = 1 \\ \\ {x}^{2} + {1}^{2} + 2 \times x \times 1 \\ = {x}^{2} + 1 + 2x$

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