Question

what is mode in Guitar ?

Answer 1

Answer:

Modes are scales derived from a parent scale. All 7 modes have the same notes as the parent scale, but start on a different note, which defines the tonal center.

Explanation:

Hope it helps...

Answer 2

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$\sf 2^x=216\ \qquad 3^y=216$

Applying logarithm on both sides ,

$\\ \longrightarrow \sf \log (2^x) = \log (216)\ \quad \log (3^y)= \log (216)$

$\longrightarrow \sf \log (2^x) = \log (6^3)\ \quad \log (3^y)= \log (6^3)$

$\boxed{ \bullet\ \; \sf \red{\log a^b = b\ \log a}}$

$\longrightarrow \sf x \log 2 = 3 \log 6\ \quad y \log 3= 3 \log 6$

$\longrightarrow \sf x = \dfrac{3 \log 6}{ \log 2}\ \quad y = \dfrac{3 \log 6}{ \log 3}$

$\longrightarrow \sf \purple{\dfrac{1}{x} = \dfrac{ \log 2}{ 3 \log 6}\ \; ; \quad \dfrac{1}{y} = \dfrac{ \log 3}{ 3 \log 6}}$

Our required value ,

$:\implies \sf \dfrac{1}{x}+\dfrac{1}{y}$

$:\implies \sf \dfrac{ \log 2}{3 \log 6}+\dfrac{\log 3}{3 \log 6}$

$:\implies \sf \dfrac{ \log 2 + \log 3}{3 \log 6}$

$\boxed{ \bullet\ \; \sf \red{\log a + \log b = \log ab}}$

$:\implies \sf \dfrac{ \log (2.3)}{3 \log 6}$

$:\implies \sf \dfrac{ \log 6}{3 \log 6}$

$:\implies \sf \dfrac{ 1 }{ 3 }\ \; \bigstar$

$\boxed{\sf \dagger\ \; \; \pink{ \dfrac{\textsf{\textbf{1}}}{\textsf{\textbf{x}}} + \dfrac{\textsf{\textbf{1}}}{\textsf{\textbf{y}}} = \dfrac{\textsf{\textbf{1}}}{\textsf{\textbf{3}}} }}$

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Shortcut :

$\sf 2^x = 3^y = 216$

$\sf \to 2 = (216)^{\frac{1}{x}}\ \; \; \& \; \; \; 3 = (216)^{\frac{1}{y}}$

Multiply both the equations ,

$\to \sf 6 = (216)^{\frac{1}{x}+\frac{1}{y}}$

$\to \sf 6 = (6)^{3 \left( \frac{1}{x}+\frac{1}{y} \right) }$

$\sf \to 1 = 3 \left( \dfrac{1}{x} + \dfrac{1}{y} \right)$

$\sf \longrightarrow \dfrac{1}{x} + \dfrac{1}{y} = \dfrac{1}{3}$