what is modulus of 1+2i/1-(1-i)^2
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Answered by
1
Given, z=1+2i/1-(1-i)^2
z=1+2i/1-(1+i^2-2i). as,i^2=-1
so,z=1+2i/1-(1-1-2i)
z=1+2i/1+2i
z=1
so, |z|=1
Answered by
0
Answer:
1
Step-by-step explanation:
Given, z=1+2i/1-(1-i)^2
z=1+2i/1-(1+i^2-2i). as,i^2=-1
so,z=1+2i/1-(1-1-2i)
z=1+2i/1+2i
z=1
so, |z|=1
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