What is molality of a 1L solution of h2so4 which is 46% wt/vol?..pls ans fst..
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46% weight/volume means, that each 100ml of solution or volume of H2SO4 solution will have 46 gm of H2SO4 .
Thus, no. of moles of H2SO4 in 100 ml of solution = 46/98 (molar mass of H2SO4 )= 0.4moles
Now, weight of 100 ml of solution = 100 x 1.40 (density) =140 gm
So, 140 gm of solution contains 46 gm of solute and (140 -46 =)94 gm of solvent.
So, in kg 94 gm of solvent = 0.095 Kg of solvent
Thus, molality of solution = moles of solute/mass of solvent in kg = 0.4/ 0.095 = 4.21
Hope it's Helpful for you.....
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