Question

What is molar volume of 60g of NH3 at STP?

Answer 1

Answer:

      V = 79g

Explanation:

No of moles(n) = given mass/molecular mass = given volume/volume at STP

given mass = 60g

molecular mass = 17g

volume at STP = 22.4L

given mass/molecular mass = given volume(V)/volume at STP

60 / 17 = V / 22.4

V = 22.4 × 60 / 17

V = 79g - molar volume

Answer 2

Answer:

*79.09*

Explanation:

mass of NH3=60g

molar mass = 17gmol-1

moles = mass/ molar mass = 60g / 17gmol-1 = 3.529 moles

as 1 mol of NH3 occupies volume at STP=22.414dm3

so,  3.529 moles of NH3 occupies volume at STP= 22.414dm3 x 3.529

                                                                             =*79.09 dm3*