Question

What is molarity ofh2so4 that has density 1.84 g/cc?

Answer 1

Answer:

As the given H₂SO₄ is 98%by wt,

Hence

100g solution contains 98g H₂SO₄ by mass

now density d=(m/v) ∴v=(m/d)

here, d=1.84g/c.c. m=100g, v=?

∴v=(100/1.84)mL= 100/ 1.84 * 1000

 again molarity= W / V * M

here weight taken W=98g, molecular weight of H₂SO₄(M)=98g/mol,

volume (V)=  100/ 1.84 * 1000

putting these values we get

∴molarity=(98*1.84*1000)/(98*100)=18.4(M)

Molarity = 18.4

Answer 2

Answer:0.01 mol per dm3

Explanation: