Question

what is mole concept calculate the
following
1. mass of 1 mole N2
2. mass of 1 mole of calcium carbonate
3. number of moles of 54 gm H2O ​

Answer 1

Explanation:

we know that=>

$1)$

$n(no \: of \: moles) = \frac{weight}{molecular \: weight} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 1= \frac{w}{14} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ 14 \: grms= w \\ 2)$\\ n = \frac{weight}{molecular \: weight} \\ 1 = \frac{w}{100} \\ w = 100 \: grms[/tex] 3)

$n = \frac{w}{m} \\ n = \frac{54}{18} \\ n = 3$

$hope \: it \: helps \: uh.....$

Answer 2

Answer:

Explanation:

we know that=>

1)1)

\begin{lgathered}n(no \: of \: moles) = \frac{weight}{molecular \: weight} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 1= \frac{w}{14} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ 14 \: grms= w \\ 2)\end{lgathered}

n(noofmoles)=

molecularweight

weight

1=

14

w

14grms=w

2)

\\ n = \frac{weight}{molecular \: weight} \\ 1 = \frac{w}{100} \\ w = 100 \: grms[/tex] 3)

\begin{lgathered}n = \frac{w}{m} \\ n = \frac{54}{18} \\ n = 3 \\\end{lgathered}

n=

m

w

n=

18

54

n=3

hope \: it \: helps \: uh.....hopeithelpsuh.....