What is mole fraction of ammonia if 51 g of ammonia is present in 90 gram of water
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Answer:
3/8
Explanation:
m. mass of ammonia(nh3) = 14+3 = 17
so, mole of ammonia in 51g = 51/17 = 3
and m. mass of water = 2+16 = 18
so, mole of water in 90g = 90/18 = 5
so, total moles are = 5+3 = 8
mole fraction of ammonia = 3 / 8
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