Question

what is momment of inertia of ring about diameter and at tangent?

Answer 1

moment of inertia about its diameter: Let I be the moment of inertia of the circular ring about its diameter XX' . Let YY' be another diameter of the ring perpendicular to the diameter XX' . Since the ring is symmetrical about its any diameter , the moment of inertia of the ring about the diameter YY' is also equal to I . According to theorem of perpendicular axes,

M.I of the ring about ZZ'= M.i about XX' +M.I about YY'

I'= I+I

I= 1I'/2

I = 1MR^2/2