what is multiplicative inverse of root 3 + 2?
usp488:
1/√5
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Heya user,
Multiplicative inverse of √3 + 2 is --->
--------> [ √3 + 2 ] ⁻¹ = 1 / [ √3 + 2 ]
{ Generally, We try to rationalize such irrational denominator }
---> Multiplying and dividing by [ √3 - 2 ] gives ->
-----> [ √3 - 2 ] / [ (√3 + 2)(√3 - 2) ]
=== [ √3 - 2 ] / [ √3² - 2² ] <----------- [ a + b ][ a - b ] = [ a² - b² ]
=== [ √3 - 2 ] / [ 3 - 4 ]
=== [ √3 - 2 ] / (-1)
=== [ 2 - √3 ] <----- Desired result ..........
Multiplicative inverse of √3 + 2 is --->
--------> [ √3 + 2 ] ⁻¹ = 1 / [ √3 + 2 ]
{ Generally, We try to rationalize such irrational denominator }
---> Multiplying and dividing by [ √3 - 2 ] gives ->
-----> [ √3 - 2 ] / [ (√3 + 2)(√3 - 2) ]
=== [ √3 - 2 ] / [ √3² - 2² ] <----------- [ a + b ][ a - b ] = [ a² - b² ]
=== [ √3 - 2 ] / [ 3 - 4 ]
=== [ √3 - 2 ] / (-1)
=== [ 2 - √3 ] <----- Desired result ..........
Nice Explanation Ansh. ^^
Gr8
yes your answer is correct but you can see the answer of other people's they are wrong I know the answer because it is in my answer book but I don't know how but now I understand and your answer is right
thank you
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