what is nature of roots of 2y square- 7 y +2 = 0
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Answer:
2y^2-7y+2=0
let a= 2 , b= -7 , c= 2
∆= b^2 -4ac
= (-7)^2 - 4(2)(2)
= 49 - 16
= 33
∆>0 , hence roots of the equation are real and unequal
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