Question

What is nature of roots of given quadratic equation? x² - 8x + 16 = 0

Answer 1

Answer:

Two equal real roots

Step-by-step explanation:

The equation is of the form ax2+bx+c=0 where:

a = 1,b = 8,c = 16

The Discriminant is given by:

= b^2 − 4⋅a⋅c

=(8)2 − (4⋅1⋅16)

=64 − 64 = 0

Answer 2

SOLUTION

TO DETERMINE

The nature of roots of given quadratic equation

${x}^{2} - 8x + 16 = 0$

EVALUATION

The given Quadratic Equation is

${x}^{2} - 8x + 16 = 0$

Comparing with

$a{x}^{2} +b x +c = 0$

We get

a = 1, b = - 8, c = 16

Now the Discriminant

$= {b}^{2} - 4ac$

$= {( - 8)}^{2} - 4 \times 1 \times 16$

$= 64 - 64 = 0$

Since the Discriminant = 0

So the roots of the equation is real & equal

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