What is newtons identity of raised power roots?
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According to Newtons identity:-
Any eqn ax²+bx+c=0 has roots a and b the n
a+b=s₁
a²+b²=s₂
a³+b³=s₃...and so on
where
s₁=ans₁+an-1=0
s₂=ans₂+an-1s₁+an-2=0...and so on
NOTE:-The power of the eqn should be equal or greater than n if we have to calculate sn.
Example-ax²+bx+c=0 and we have to calculate s₃
then f(x)=x(ax²+bx+c)=ax³+bx²+cx=0
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Any eqn ax²+bx+c=0 has roots a and b the n
a+b=s₁
a²+b²=s₂
a³+b³=s₃...and so on
where
s₁=ans₁+an-1=0
s₂=ans₂+an-1s₁+an-2=0...and so on
NOTE:-The power of the eqn should be equal or greater than n if we have to calculate sn.
Example-ax²+bx+c=0 and we have to calculate s₃
then f(x)=x(ax²+bx+c)=ax³+bx²+cx=0
PLEASE MARK AS BRAINLIEST IF HELPFUL!
Answered by
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It is the sum of roots of an equation raised to a power n defined as sn where the function may not have lower power than that of the newton constant n.
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