what is normality of a solution that contains 4.5g of oxalic acid in 300 ml of solution
Answers
Answer:
Molar mass of the Oxalic acid = 126 g/mole.
Mass of the Oxalic acid = 3.15 g.
∴ No. of moles of the Oxalic Acid = 3.15/126
= 0.025
Volume of the Oxalic acid solution. = 250 mL.
= 0.25 L.
For Molarity,
∵ Molarity = No. of moles of Solute/Volume of the Solution in L.
∴ Molarity = 0.025/0.25
= 0.1 M.
For Normality,
Equivalent Mass = 126/2 [∵ Basicity of Oxalic Acid is 2.]
= 63
No. of grams equivalent = Mass/Equivalent Mass
= 3.15/63
= 0.05
∵ Normality = No. of grams Equivalent/Volume of the Solution in L.
∴ Normality = 0.05/0.25
= 0.2N...
Explanation:
Answer:
Explanation:
Definition of normality:
The amount of grammes or mole equivalents of solute present in a solution that contains one liter is what is referred to as normalcy according to the accepted definition. The amount of moles of reactive units in a compound is what we mean when we say it is equal.
Formulas for Normality:
The normalcy equation is given by, which aids in estimating the volume of a solution needed to make a solution of a different normality.
Initial Normality (N1) x Initial Volume (V1) equates to Initial Normality (N2) x Final Volume for the final solution (V2)
Assuming that four distinct solutions containing the same solute of normalcy and volume are combined, the new normality is given by;
NR = [Va+Vb+Vc+Vd]-1 [NaVa + NbVb + NcVc + NdVd]
The resultant normalcy is provided by; when four solutions with varied solute of molarity, volume, and H+ ions (na, nb, nc, nd) are mixed.
NR = [Va+Vb+Vc+Vd]-1 + [naMaVa + nbMbVb + ncMcVc + ndMdVd].
Given:
Oxalic acid has a molar mass of 126 g/mole.
Mass of Oxalic acid = 4.5g
Find:
Normality
Solution:
Number of Oxalic Acid Molecules = 4.5/126
= 0.035
300 mL is the size of the oxalic acid solution.
= 0.35 L.
For Molarity,
∵ Molarity = No. of moles of Solute/Volume of the Solution in L.
∴ Molarity = 0.035/0.35
= 0.1 M.
For Normality,
Equivalent Mass = 126/2 [∵ Basicity of Oxalic Acid is 2.]
= 63
No. of grams equivalent = Mass/Equivalent Mass
= 4.5/63
= 0.07
∵ Normality = No. of grams Equivalent/Volume of the Solution in L.
∴ Normality = 0.07/0.35
= 0.2N...
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