What is Normality?.
What is Molarity?
What is Morality?
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College Chemistry : Molarity, Molality, Normality
Study concepts, example questions & explanations for College Chemistry
Example Questions
College Chemistry Help » Solutions, States of Matter, and Thermochemistry » Liquids and Solutions » Molarity, Molality, Normality
Molarity, Molality, Normality : Example Question #1
A solution is prepared by dissolving 10.2g of glucose, C6H12O6, in 405g of water. The final volume of the solution is 414mL. Find the concentration of the solution in units of molality.
Possible Answers:
0.135m
0.122m
0.149m
0.140m
Correct answer:
0.140m
Explanation:
Recall how to find the molality of a solution:
Molality=moles of solutekg of solvent
First, start by finding the moles of glucose that we have. The molar mass of glucose is 180.16g/mol.
10.2g of glucose⋅1 mole glucose180.16g of glucose=0.0566 moles of glucose
Next, convert the grams of water into kilograms.
405g⋅1kg1000g=0.405kg
Now, plug in the moles of glucose and kilograms of water into the equation for molality.
Molality=0.05660.405=0.140m
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Molarity, Molality, Normality : Example Question #2
A solution of hydrogen peroxide is 15.2% by mass. What is the molarity of the solution? Assume that the solution has a density of 1.01g/mL.
Possible Answers:
5.00M
4.95M
3.72M
6.02M
Correct answer:
4.95M
Explanation:
Start by assuming that we have 1.00L of this solution. Recall that hydrogen peroxide has a molecular formula of H2O2.
Use the given density to find the mass of the solution.
1.00L⋅1000mL1L⋅1.01gmL=1010g
Next, find the mass of the hydrogen peroxide present in the solution.
1010g(0.152)=153.52g
Convert the mass of hydrogen peroxide into moles of hydrogen peroxide.
153.52g of H2O2⋅1 mole H2O231.04g H2O2=4.95 moles of H2O2
Recall how to find the molarity of a solution:
Molarity=moles of soluteliters of solution
Since we have 1.00L of solution, the molarity is 4.95M.
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Molarity, Molality, Normality : Example Question #3
What is the molarity of a solution in which 211g sodium hydrogen carbonate is dissolved in a 10.0L solution?
Possible Answers:
0.333M
0.213M
0.251M
2.51M
2.13M
Correct answer:
0.251M
Explanation:
211g sodium hydrogen carbonate dissolved in a 10.0L solution has 0.251M.
The first step is to calculate how many moles of NaHCO3 are present. 211gNaHCO31molNaHCO384.006gNaHCO3=2.51molNaHCO3
We calculate molarity with the following equation:
M=molesofsolutelitersofsolution
M=2.51molesNaHCO310L=0.251M