Question

What is observed when a solution of potassium iodide is added to a solution of lead acetate in a test tube.
1. What type of reaction is this.
2. Write a balanced chemical equation to represent the above equation

Answer 1

Question:

What is observed when a solution of potassium iodide is added to a solution of lead acetate in a test tube.

1. What type of reaction is this.

2. Write a balanced chemical equation to represent the above equation?

Answer:

◆ When a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube, the precipitation of a yellowish solid is observed. This yellowish solid is lead iodide. Potassium nitrate is formed along with lead iodide.

◆ This is a double displacement reaction.

◆ When the two ionic compounds / elements exchange their ions is called Double Displacement Reaction.

◆ The balanced chemical equation for the above reaction is:

Balanced Equation: Pb(NO3)2 + 2KI --- 2KNO3 + PbI2

Word Equation: lead nitrate + Potassium Iodide ---- Potassium Nitrate + Lead Iodide.

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Answer 2

answer:

Hi there !!

Lead nitrate = Pb[NO]₂

Potassium Iodide = KI

When Lead Nitrate and Potassium Iodide are mixed we get Potassium Nitrate and an insoluble solid [ precipitate ] lead iodide.

Colour of the precipitate formed is Yellow [ Lead Iodide ]

KI + Pb[NO₃]₂ -----> KNO₃ + PbI₂

-----> UNBALANCED EQUATION

2Kl+ Pb[NO₃]₂ -----> 2KNO₃ + PbI₂

----> BALANCED EQUATION

This is an example of double displacement reaction.

Also , as yellow precipitate is formed , this is also an example of precipitation reaction