What is observed when a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube ? (ii) What type of reaction is this ? (iii) Write a balanced equation to represent the above reaction.
Answers
Answer:
When a solution of potassium iodide (KI) is added to a solution of lead nitrate (PbNO3), a yellow precipitate is formed. It is lead iodide (PbI).
This is a double displacement reaction.
Equation:
2KI (aq.) + Pb(NO3)2 (aq.) → PbI2 (s) + 2KNO3 (aq.)
KI - Potassium iodide
Pb(NO3)2 - Lead nitrate
PbI2 - Lead iodide
KNO3 - Potassium nitrate
Answer:
When a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube, the precipitation of a yellowish solid is observed. This yellowish solid is lead iodide. Potassium nitrate is formed along with lead iodide. This is a double displacement reaction.
1) The five basic types of chemical reactions are combination, decomposition, single-replacement, double-replacement, and combustion. Analyzing the reactants and products of a given reaction will allow you to place it into one of these categories.
2) jo photo me hai vo 2nd ka answer hai
