Question

What is observed when a solution of potassium iodine is added to lead nitrate solution? a) What type of reaction is this? b) Write a balance chemical equation for this reaction?​

Answer 1

Answer: when a solution of potassium iodide is added to the lead nitrate solution it exchanges their ions to form potassium nitrate and lead iodide...

PbNO3+kI=KNO3+PbI

a) it is a double displacement reaction...

b) Above is the balanced equation.....

Explanation:

HOPE IT HELPS YOU FRND.......

Answer 2

$\huge\tt{Answer:-}$

When a solution of potassium iodide is added to a solution of lead nitrate, the precipitation of a yellowish solid is observed. This yellowish solid is lead iodide. Potassium nitrate is formed along with lead iodide.

$\sf a) \: This \: is \: a \: double \: displacement \: reaction.$

$\sf b) \: Pb(NO_{3})_{2} (aq) + 2KI(aq)$ $\sf ➝ PbI_{2} (s) + 2KNO_{3} (aq)$

$\sf Or$

$\sf Lead \: nitrate + Potassium \: iodide$ $\sf ➝ Lead \: iodide(YellowPPt.) + Potassium \: nitrate$