what is one digit number
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Hey,sup!
As per the question,
=17^1999 +11^1999-7^1999.
=(17^4)^499 × 17^3 + 11^1999 - (7^4)^499×7^3.
=(1)^499×3+(1)^1999-(1)^499×3.
=3+1-3.
=1.
The unit digit will be 1.
Hope it helps.
As per the question,
=17^1999 +11^1999-7^1999.
=(17^4)^499 × 17^3 + 11^1999 - (7^4)^499×7^3.
=(1)^499×3+(1)^1999-(1)^499×3.
=3+1-3.
=1.
The unit digit will be 1.
Hope it helps.
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