what is (or) are the zeroes for 4x^2-2x-2=0
Answers
Answered by
0
4 x²-2x-2=0
⇒ 2(2x²-x-1)=0
⇒ 2(2 x²-x+2x-1)=0
⇒ 2[x(2x-1)+1(2x-1)]=0
⇒ 2(x+1)(2x-1)=0
therefore, either x= -1 or x= 1/2
⇒ 2(2x²-x-1)=0
⇒ 2(2 x²-x+2x-1)=0
⇒ 2[x(2x-1)+1(2x-1)]=0
⇒ 2(x+1)(2x-1)=0
therefore, either x= -1 or x= 1/2
Anonymous:
It is -1/2. :) Plz check and correct it. :)
thanks
Answered by
0
Q. 4x²-2x-2
= 4x²-4x+2x-2
= 4x(x-1)+2(x-1)
= (x-1) (4x+2)
α⇒x-1=0
α = x=1
α=1
β⇒ 4x+2=0
4x=-2
x=-2/4
x=-1/2
β= -1/2
Hence, the two zeroes are 1 and -1/2.
= 4x²-4x+2x-2
= 4x(x-1)+2(x-1)
= (x-1) (4x+2)
α⇒x-1=0
α = x=1
α=1
β⇒ 4x+2=0
4x=-2
x=-2/4
x=-1/2
β= -1/2
Hence, the two zeroes are 1 and -1/2.
I hope it may help you.
Thank you so much...
np :)
thanks
Similar questions