Chemistry, asked by lisasharma3527, 1 year ago

What is order with respect to A, B, C, respectively
[A]
0.2
0.1
0.1
0.2

[B]
0.1
0.2
1.8
0.1

[C]
0.02
0.02
0.18
0.08

rate (M/sec.)
8.08 × 10⁻³
2.01 × 10⁻³
6.03 × 10⁻³
6.464 × 10⁻²

(a) –1, 1, 3/2
(b) –1, 1, 1/2
(c) 1, 3/2, –1
(d) 1, –1, 3/2

Answers

Answered by rohithgowdabs
0

this the answer of thid

Attachments:
Answered by rpraveenrajesh
0

ANSWER

The rate law expession is r=k[A]

x

[B]

y

[C]

z

.

From first and second experimnt,

0.0×10

−3

=k 0.2

x

0.1

y

0.02

z

2.01×10

−3

=k 0.1

x

0.2

y

0.02

z

(2)×(

2

1

)

y

=4

x−y=2 ......(1)

From second and third experiment

2.01×10

−3

=k 0.1

x

0.2

y

0.02

z

6.03×10

−3

=k 0.1

x

1.8

y

0.18

z

(9)

y

(9)

z

=3

2y+2z=1 ......(2)

From first and fourth experiment, 4

z

=8=2

3

0.0×10

−3

=k 0.2

x

0.1

y

0.02

z

6.464×10

−2

=k 0.2

x

0.1

y

0.08

z

2z=3 ......(3)

From equations (1), (2) and (3), we get, x=1, y=−1, z=3/2

Thus, order with respect to A, B, C is 1,−1,3/2 respectively.

Hence, the correct option is D

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