What is oxidation no. Of zn in zn(oh)4-
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Oxidation 4? Zn + 4 OH - ? Zn(OH)42? + 2 e -]
Reduction NO3- + 6 H2O + 8 e - ? NH3 + 9 OH -
Overall 4 Zn + NO3- + 6 H2O + 7 OH - ? 4 Zn(OH)42? + NH3
Explanation:
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