Question

What is oxidation number of iodine in NaIO3

Answer 1

Oxidation number refers to the charge that an atom in a compound holds when the compound is completely or fully ionic.

Oxidation number determining has a set of simple rules by which they can be reached at. The oxidation number of Iodine in NalO3 is +5.

The oxidation of Na = +1, O = -2, and eventually I = +5

Answer 2

Oxidation number of iodine in $NaIO_3$ is +5.

Explanation:

• In simple words oxidation number can be defined as the number of electrons lost by an atom to form the neutral compound.

• The oxidation number of Iodine can be calculated as the oxidation number of sodium is +1 and that of oxygen is -2 .

• We also know the overall charge on a compound must be 0.

• So, the calculation is as follows:

• $NaIO_3$ =  (1) + (x) + (-2)x3 =-6 ; where x is the oxidation

• number of Iodine

• So, 1 + x -6  $\rightarrow$ x = 6-1=5 hence the oxidation number of

          iodine is +5.

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