Question

what is oxidation number of P in H3PO4

Answer 1

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Answer 2

Oxidation number of P in $H_3PO_4$ is +5.

Explanation:

• The given compound is phosphoric acid, in which hydrogen is bonded with non-metal.
• Due to such bonding hydrogen has +1 charge whereas oxygen has -2 charge within a compound.
• As the given compound is neutral, its total charge is equal to 0.
• To calculate the oxidation number of P, an equation must be written which is as follows:

3 H + 1 P + 4 O = 0

Substituting the charges in the above equation, it gives

3 (+1) + 1 (X) + 4 (-2) = 0

3 + X -8 = 0

X -5 = 0

X = +5.

• Thus oxidation number of P in $H_3PO_4$ is calculated as +5.

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