What is Oxidation state of fe in mohr salt
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21
The oxidation state of Fe in Mohr salt is +2.
Suraj1023:
Can u explain it plz
Mohr's salt = Fe(NH4)2(SO4)2.6H2O --------------- (1)
Oxidation nos of Fe is given as: x
Oxidation nos of NH4 = +1
Oxidation nos of SO4 = -2
Oxidation nos of H = +1
Oxidation nos of O = -2
Substitute values in (1) we get
x + 2(+1) + 2(-2) + 6(2(1) - 2) = 0
x + 2 - 4 + 6[2 - 2] = 0
x - 2 + 6(0) = 0
x - 2 + 0 = 0
x - 2 = 0
x = 2
Oxidation nos of Fe is given as: x
Oxidation nos of NH4 = +1
Oxidation nos of SO4 = -2
Oxidation nos of H = +1
Oxidation nos of O = -2
Substitute values in (1) we get
x + 2(+1) + 2(-2) + 6(2(1) - 2) = 0
x + 2 - 4 + 6[2 - 2] = 0
x - 2 + 6(0) = 0
x - 2 + 0 = 0
x - 2 = 0
x = 2
Answered by
8
Answer : The oxidation state of Fe in mohr salt is, (+2)
Explanation :
The formula of the mohr salt is,
Mohr salt is also known as ammonium ferrous sulfate or ammonium iron(II)sulfate. It is the inorganic compound which containing two different cations which are and
. It is classified as a double salt of ferrous sulfate and ammonium sulfate.
In ferrous sulfate, sulfate is a polyatomic anion which has (-2) charge. So, (+2) charged iron is needed to neutralize the (-2) charge of sulfate ion.
Hence, the oxidation state of Fe in mohr salt is, (+2)
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