What is percentage strength for 3percent h2o2
Answers
Answer:
Answer: Volume strength of H_2O_2H
2
O
2
is 9.856.
Explanation: Volume strength of H_2O_2H
2
O
2
is defined as the amount of O_2O
2
released.
Strength of any solution can be calculated as:
Strength = Normality × Equivalent weight
Normality is calculated as:
Normality=\frac{\text{Given mass of solute (in grams)}}{\text{Equivalent weight}\times \text{Volume (in L)}}Normality=
Equivalent weight×Volume (in L)
Given mass of solute (in grams)
We are given 3% (w/v) solution of H_2O_2H
2
O
2
which means that 3 grams of hydrogen peroxide is present in 100 mL of solution.
Equivalent mass of H_2O_2=\frac{34}{2}=17g/eqH
2
O
2
=
2
34
=17g/eq
Normality=\frac{3g}{17g/eq\times 0.1L}Normality=
17g/eq×0.1L
3g
Normality = 29.92 eq/L
Now, 3 gram of H_2O_2H
2
O
2
gives 22400mL of O_2O
2
at STP
So, (1.76×17)g of H_2O_2H
2
O
2
will give = \frac{22400\times 1.76\times 17}{68}
68
22400×1.76×17
= 9856mL of O_2O
2
at STP
But, (1.76×17)g of H_2O_2H
2
O
2
is present in 100mL of H_2O_2H
2
O
2
solution.
Therefore, 1000mL of H_2O_2H
2
O
2
solution gives 9856mL of O_2O
2
at STP.
1mL of H_2O_2H
2
O
2
will give = \frac{9856}{1000}mL
1000
9856
mL of O_2O
2
at STP.
= 9.856mL of O_2O
2
at STP.
Hence, the volume strength of 1.76N of H_2O_2H
2
O
2
solution is 9.856 volume.