Question

what is perimeter of this rectangle 20 CM 5 cm​

Answer 1

Step-by-step explanation:

first we have to find breadth so area of perimeter=2×(l+b)

so 20=2×(5+b)

20=10+2b

20-10=2b

10=2b

b=5cm

then we have to apply pythagoras theorm so it is h^2=p^2+b^2

h^2=25+25

h^2=50

h=

\sqrt{50}

50

h=7.3cm

this is diagonal

area =l×b

=5×5

=25cm^2

Answer 2

Answer:

Perimeter of rectangle = 2 × (L × B)

= 2 × (20 cm + 5 cm)

= 2 × 25 cm

= 50 cm

Hope it helps you dear friend.

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