Question

What is perimeter of whose vertices are (0,4),4(4,0),(3,0)

Answer 1

First find length of each sides of ∆ 
Let A( 4 , 0) B(0, 0) and C (0 , 3) 

use distance formula, 
AB =√(4²+0) =4 
BC= √(0+3²) = 3
CA =√(4²+3²) =5 

now ,
perimeter of ∆ = 3 + 4 + 5= 12 unit