Question

What is periphery of a rectangle ABCD, if AD = 3 and BD =5 ?

Answer 1

Answer:

Step-by-step explanation:

AD=3 that is breadth and BD=5that is diagonal

By using Pythagoras theorem,

h^2=p^2+b^2

(5)^2=(3)^2+b^2

25=9+b^2

25-9=b^2

16=b^2

root 16=b

4=b

Now length is 4

Perimeter of rectangle=2(l+b)

=2(4+3)

=2 x 7

=14

Hope my answer will help you...