Question

what is pH of 1 M calcium lactate (Ca(lac)2 and 1 M lactic acid buffer solution if Pka of lactic acid is 3.08​

Answer 1

Answer:

The pH of the solution is 3.08.

Explanation:

Given data:

Concentration of Calcium lactate = 1 M

Concentration of lactic acid = 1 M

pka of lactic acid = 3.08

To find: pH value of the solution

We know, the pH of an acidic solution is given by,

pH = pKa + log₁₀ $\frac{[calcium lactate]}{[lactic acid]}$

⇒ pH = 3.08 + log₁₀ $\frac{1 M}{1 M}$

⇒ pH = 3.08 + log₁₀ (1)

∵ log₁₀ (1) = 0  

or, pH = 3.08