Question

What is ph of solution containing 4g naoh and 1 litre water?

Answer 1

Answer:

13

Explanation:

Moles of NaOH = 4g / (40 g/mol) = 0.1 mol

Molarity of NaOH = 0.1 mol / 1 Litre = 0.1 molar

[OH-] = 0.1

pOH = -log[OH-]

= - log(0.1)

= 1

pH = 14 - pOH

= 14 - 1

= 13

pH of given NaOH solution is 13

Answer 2

Answer:

pH=12

Step-by-step explanation:

NaOH ---------> Na+ + OH-

NaOH ---------> Na+ + OH-Strong base completely dissociates,

NaOH ---------> Na+ + OH-Strong base completely dissociates,therefore

$(oh - ) = \frac{0.4}{40} mol \: l = {10}^{ - 2}$

$(oh - )(h + ) = {10}^{ - 14} m$

$(h + ) = {10}^{ - 2} m$

$ph = - log(h + )$

$ph = - log( {10}^{ - 12} ) \\ = 12$