Question

what is pOH of 0.02M of Ca(OH)2​

Answer 1

Answer:

I will answer assuming you mean :

What is the pOH of 0.02 M Ca(OH)2

Ca(OH)2 is a strong base that dissociates completely

Ca(OH)2(aq) → Ca2+ (aq) + 2 OH- (aq)

Therefore [OH-] = 0.04M

pOH = - log [OH-]

pOH = - log 0.04

pOH = 1.40

And for completion:

pH = 14.00 - 1.40 = 12.60